Tricks et algorithmes qui aident
Directory
How many digits in a number (py)
from math import log10
def digitsNb(n):
return log10(n)+1
tab = [1,12,123,1234,12345,123456]
for i in tab:
print(int(digitsNb(i)), end=' ')
# output : 1 2 3 4 5 6
Digit extraction (py)
def digitExtract(n, pos):
return (n//(10**pos))%10
for i in range(3,-1,-1):
print(digitExtract(3684,i), end='|')
# output: 3|6|8|4|
Nice round (Cpp)
Le cast en int (py ou cpp) va suprimer la décimale peu importe sa valeur.
Le + .5 avant le cast sur tot assure que la valeur après le cast sera arrondie en fonction de la décimale.
int main() {
double a = 10.25;
int b = 17;
int c = 5;
float B = static_cast<float>(b);
float C = static_cast<float>(c);
float tot = a + (a*(B/100)) + (a*(C/100));
cout << "The total meal cost is " << static_cast<int>(tot + .5)
<< " dollars." << endl;
return 0;
}